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year(aDate[, yearsNum])


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 Function  [other Function type actions]

 Item  [operators of similar scope]

 Date-time  [other Date-time operators]

 Baseline

 As at baseline

 [More on optional operator arguments]

Yes


year(aDate[, yearsNum])

Alternatively, use Date.year.

year(aDate)

returns the year from the theDate date/time expression:

$MyNumber = year($MyDate); 

year(aDate,value)

creates a new date based on the theDate date/time expression, but in which the year is yearsNum. aDate is not changed unless theDate is an attribute and the attribute is re-setting itself:

$MyDateA = year($MyDate,2011); $MyDate is unaltered

$MyDate = year($MyDate,2011); $MyDate is changed

Examples. If $MyDate is July 4,2009, then

$MyDate=hour($MyDate,2011); 

will change $MyDate to July 4, 2011.